Answer:
<em>$7,196.42 </em>
Step-by-step explanation:
Using the compound interest formula to fins the amount after 10years;
A = P(1+r)^n
Principal P = $400,000
Rate r = 8% = 0.08
Time t = 10 years
Substitute
A = 400,000(1+0.08)^10
A = 400,000(1.08)^10
A = 400,000(2.1589)
A = 863,569.99
A ≈ 863,570
Hence the amount after 10 years is $863,570
Monthly deposit = $863,570/120 (10 years is equivalent to 120months)
Monthly deposit = 7,196.42
<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>
I got x < 2 for the inequality
Look at the image for more information
Answer:
x=10/3 y=17/3
Step-by-step explanation:
Use substitution to solve your equation. Plug in y=2x-1 into y=1/2x+4. This makes (2x-1)=1/2x+4. Simplify this to get 3/2x-1=4. Simplify it again to get 3/2x=5. No one likes fractions so multiply both sides by 2 to get 3x=10. Simplify this and get x=10/3. Plus 10/3 into one of the equations. You can pick anyone but I picked y=2x-1. Because you know x=10/3, you put y=2(10/3)-1. Simplify this and get y=20/3-1. Convert 1 into a fraction and get y=20/3-3/3. Simplify this and get y=17/3.
Therefore,
x=10/3 y=17/3
Hoped this helps you
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
