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Mama L [17]
2 years ago
7

Shirts are on sale for $12 at a clothing store. How many shirts can you buy with $48?

Mathematics
2 answers:
blagie [28]2 years ago
6 0

Answer:

4 if no tax is included because 4 times 12 equals 48

hope this helps

Step-by-step explanation:

BaLLatris [955]2 years ago
5 0

Answer:

4 shirts in total,

12x4=48

Step-by-step explanation:

Hope this helps!

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in last weeks volleyball game Ashley served 15 times and made 2 errors. What was her serving percentage? (what percent did she s
Setler79 [48]
1300%


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7 0
3 years ago
How can you add decimals without a place-value chart to make sure you are adding
Semmy [17]

Answer:

You can make sure that you align the decimal dots together.

Step-by-step explanation:

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You can see that the decimal dot is aligned.

6 0
3 years ago
What’s the answer?!!
Grace [21]

Answer:

6x+10mm=p is the answer

brainlest plz

6 0
3 years ago
A machine manfactures wheels with a diameter of 70cm. It is acceptable for the diameter of a wheel to be within 0.02cm of this v
vitfil [10]

The expected diameter is 70 cm.


It is acceptable for the diameter to be within 0.02 cm of the expected value.

Therefore the acceptable values for the diameter, d, are



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d + 0.02 = 70

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The maximum acceptable value of d is obtained from

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d = 70.02 cm


Answer:

Minimum acceptable diameter = 69.98 cm

Maximum acceptable diameter = 70.02 cm

5 0
3 years ago
Write the equation of the circle by completing the square.<br><br> x'2 + 4x + y'2 - 2y = 20
evablogger [386]
\bf \textit{let's start by grouping}&#10;\\\\\\&#10;x^2+4x+y^2-2y=20\implies (x^2+4x)+(y^2-2y)=20&#10;\\\\\\&#10;(x^2+4x+\boxed{?}^2)+(y^2-2y+\boxed{?}^2)=20

so hmm we're missing a couple of folks, one in each group, to get a perfect square trinomial

now, recall \bf \begin{array}{cccccllllll}&#10;{{ a}}^2& + &2{{ a}}{{ b}}&+&{{ b}}^2\\&#10;\downarrow && &&\downarrow \\&#10;{{ a}}&& &&{{ b}}\\&#10;&\to &({{ a}} + {{ b}})^2&\leftarrow &#10;\end{array}\qquad &#10;%   perfect square trinomial, negative middle term&#10;\begin{array}{cccccllllll}&#10;{{ a}}^2& - &2{{ a}}{{ b}}&+&{{ b}}^2\\&#10;\downarrow && &&\downarrow \\&#10;{{ a}}&& &&{{ b}}\\&#10;&\to &({{ a}} - {{ b}})^2&\leftarrow &#10;\end{array}

so.. the middle term of a perfect square trinomial, is really 2 * the other 2 guys

so hmm we can say 2 * x * ? = 4x, thus 2x * ? = 4x, thus cross-multiplying
? = 2

now, for the other, 2 * y * ? = 2y, thus 2y* ? = 2y thus ? = 1

so our guys are 2 and 1

now, bear in mind, all we're doing, is borrowing from our very good friend Mr Zero, 0, so, if we add whatever, we also have to subtract whatever

thus   \bf (x^2+4x+2^2)+(y^2-2y+1^2)-1^2-2^2=20&#10;\\\\\\(x^2+4x+4)+(y^2-2y+1)-5=20\\\\\\ \boxed{(x+2)^2+(y-1)^2=25}\\\\&#10;-----------------------------\\\\&#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad center\ ({{ h}},{{ k}})\qquad&#10;radius={{ r}}\\\\&#10;-----------------------------\\\\&#10;(x-(-2))^2+(y-1)^2=5^2\qquad center\ (-2,1)\qquad radius=5
4 0
3 years ago
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