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2 years ago

Plz help convert and show work plz!

Mathematics

1 answer:

valina [46]2 years ago

8 0

Answer:

1) 5280 feet/sec

2)$3.41

Step-by-step explanation:

60 miles is 316800 feet, divided by 60 which is 5280 feet/sec

2)2.4x1.42 is 3.41

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Evaluate the function represented by the graph for f(-2).

Alex_Xolod [135]

Answer:

f(-2) = 2

Step-by-step explanation:

The question is asking you to find the y value when the x value is -2. When observing the graph, we can see when the x value is -2, the y value is 2. Therefore, f(-2) = 2.

4 0

2 years ago

What is the written expanded form of 327.46

irinina [24]

The answer is 30000+2000+700+40+6

6 0

3 years ago

Read 2 more answers

-2(y+12)=y-9

lions [1.4K]

1) y= -5

2) m = -1

3) k = 3

4) y = -5

Step-by-step explanation:

1) $-2(y+12)=y-9$

Solving:

$-2(y+12)=y-9\\-2y-24=y-9\\Combining\,\,like\,\,terms:\\-2y-y=-9+24\\-3y=15\\y=15/-3\\y=-5$

2) $8(-1+m)+3 = 2 [m-5 1/2]\\$

Solving:

$8(-1+m)+3 = 2 [m-5 \frac{1}{2} ]\\-8+8m+3=2 [m-\frac{11}{2} ]\\8m-5=2 [\frac{2m-11}{2} ]\\8m-5=2m-11\\Combining\,\,like\,\,terms:\\8m-2m=-11+5\\6m=-6\\m=-6/6\\m=-1$

3) $8(12-k)=3(k+21)$ (Note: Considering 8(12-k)=3(k+21) instead of 8(12-k)=3(k=k+21))

Solving:

$8(12-k)=3(k+21)\\96-8k=3k+63\\Combining\,\,like\,\,terms:\\-8k-3k=63-96\\-11k= -33\\k=-33/-11\\k=3$

4) $2y-3(2y-3)+2=31$

Solving:

$2y-3(2y-3)+2=31\\2y-6y+9+2=31\\Combining\,\,like\,\,terms:\\2y-6y=31-9-2\\-4y=20\\y= 20/-4\\y = -5$

Keywords: Solve for variables.

Learn more about Solve for variables at:

#learnwithBrainly

6 0

3 years ago

That is not the answer

user100 [1]

What is not the answer boaaaa

6 0

3 years ago

Use the following matrices, A, B, C and D to perform each operation.

wolverine [178]

Step-by-step explanation:

$\bold{40.}\\\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right] +\left[\begin{array}{ccc}4&1\\6&0\end{array}\right] =\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&1\\11&7\end{array}\right]$

$\bold{41.}\\\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$\bold{42.}\\\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$\bold{43.}\\\\CD=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\\\=\left[\begin{array}{ccc}4+0+1&-6-6+4&-8+3-1\\2+0+12&-3+0+16&-4+0-4\end{array}\right]\\\\=\left[\begin{array}{ccc}5&-8&-6\\14&13&-8\end{array}\right]$

$\bold{44.}\\\\2D+3C=2\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]+3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\\\\=\left[\begin{array}{ccc}(2)(-2)&(2)(3)&(2)(4)\\(2)(0)&(2)(-2)&(2)(1)\\(2)(3)&(2)(4)&(2)(-1)\end{array}\right]+\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]\\\\=\left[\begin{array}{ccc}-4&6&8\\0&-4&2\\6&8&-2\end{array}\right]+\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$\large\bold{You\ can\ not\ add\ matrices\ of\ different\ dimensions!!!}$

4 0

2 years ago