the given expression is,
4 = 5x + 6y
6y = 4 - 5x
y = 4/6 - 5/6x
y = 2/3 - 5/6x
so, the answer is y = 2/3 - 5/6x
10+2 x n +4
(N is the quantity of a number)
32
31.832142857 is what you got, look at your tenths digit. if it's greater or equal to 5, it will always round to the higher number. if its less than or equal to 4, it will be the lower number.
for example, 10.4 will be 10, as it is lower than 5
or 10.6 will be 11 cause it is higher than 5
Answer:
2(7) - 1/4 = 4 + 1/3x
x = 117/4
Step-by-step explanation:
solving an equation with one missing variable
step 1: multiply 2 * 7
ex: 14 - 1/4 = 4 + 1/3x
step 2: subtract 14 from 1/4
ex: 55/4 = 4 + 1/3x
step 3: subtract 4 from both sides of the equation
55/4 - 4 = 4 + 1/3x - 4 (39/4 = 1/3x)
step 4: divide both sides of the equation by 1/3
ex: 39/4 / 1/3 = 1/3x / 1/3 (x = 117/4 or x = 29 1/4)
step 5: to check your answer add the answer you got from the last equation which was 117/4 or 29 1/4 and input it into the original equation and get your final answer
ex: 2(7) - 1/4 = 4 + 1/3(117/4)
14 - 1/4 = 4 + 39/4
55/4 = 55/4 (if both sides of the equation are the same numbers like 55/4 = 55/4 then your answer is true)
Answer:
x= 3
y=2
Step-by-step explanation:
-3x + 9y = 9 ----------- equation 1
3x + 2y = 13--------------- equation 2
In Matrix Form
![\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%269%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
Let A = ![\left[\begin{array}{cc}-3&9\\3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%269%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D)
X = ![\left[\begin{array}{c}x\\y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D)
and B = ![\left[\begin{array}{c}9\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
Then Mathematically AX= B
or X= A⁻¹ B
Where A⁻¹ = Adjacent A/ mod of A
Adjacent A = ![\left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-9%5C%5C-3%26-3%5Cend%7Barray%7D%5Cright%5D)
Mod Of A= -6 - (27) = -33 which is not equal to zero
so Putting These values in the given formula
X= 1/-33
Now Multiplying Rows and Columns
= -1/33 ![\left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%2A9%2B-%209%2A13%5C%5C-3%2A9%20%2B-%203%2A13%5Cend%7Barray%7D%5Cright%5D)
Solving the Matrix we get
= -1/33 ![\left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D18-117%5C%5C-27-39%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= -1/33 ![\left[\begin{array}{cc}-99\\-66\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-99%5C%5C-66%5Cend%7Barray%7D%5Cright%5D)
From Here we find x= 99/33 or 3
and y = 66/33= 2
