The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
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2) c
3) d
4) a
5) d
6) c
7) a
8) b
Answer:
x greater than or equal to 5
Now: a=j+4
6 years ago: Anabelle: a-6; Jason: j-6
Answer:
y = 0.55 or 5 / 9
Step-by-step explanation:
here's the solution :-
=》y + 7 = 19y - 3
=》7 + 3 = 19y - y
=》18y = 10
=》y = 10 ÷ 18
=》y = 5 ÷ 9
=》y = 0.55
