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Shalnov [3]
3 years ago
15

If U answer right I will mark brainliest and give 30 points

Mathematics
2 answers:
erik [133]3 years ago
7 0

Answer:

B. 25 cubic units because you just add all the sides together

aleksandr82 [10.1K]3 years ago
5 0

Answer:

25 cubic units

Step-by-step explanation:

Formula would be V = Bh

Basically, just multiply 2.5 x 2.5 x 4

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Use the distributive property to write an equivalent expression.<br> -(0-2)
Savatey [412]

Answer:

0+2 or simply 2

Step-by-step explanation:

just imagine a "1" by the minus

-1(0-2)

5 0
3 years ago
1. Mrs. Jones picks 3 flowers a day starting on Monday. How many does she have by Sunday?
Aleks04 [339]

Answer:

1. 18

2. 2412

Step-by-step explanation:

1. Monday 3

Tuesday 6

Wensday 9

Thursday 12

Friday 15

Sunday 18

_____________________________________________________

2.

603*4=2412

3 0
3 years ago
I need help with a prople on my math for 8 grade it is y = -8x - 2
Nadusha1986 [10]

Answer:

M=8 Y=-2

Step-by-step explanation:

this is the slope and b

8 0
3 years ago
A Create a linear expression
frez [133]

Answer:

(2x+A)(2x+B) = 4x2 + (2B+ 2A)x + AB. Trial and error gives the factorization 4x2 - 3x - 10 - (4x+5)(x- 2) .Step-by-step explanation:

3 0
2 years ago
Meenu bought two fans for ₹1200 each. She sold one at a loss of 5% and the other at a profit of 10%. Find the selling price of e
Vinvika [58]
<h3><u>Solution: </u></h3>

Overall<u> </u>CP of each fan = ₹1200 .

One is sold at a loss of 5% .

  • ( This means if CP is ₹100, SP is ₹95 ) .

• Therefore,When CP is ₹1200 , Then SP is ₹ 1140.

=  >  \frac{95}{100}  \times 1200 = 1140

Also,Second fan is sold at a profit of 10% .

  • It means , If CP is ₹100 , SP is ₹110.

Therefore , When CP is ₹1200 , Then SP is ₹1320.

<u>• We need to find the combined CP and SP to say whether there was an overall profit or Loss.</u><u>.</u>

  • Total CP = ₹ 1200 + ₹ 1200 = ₹ 2400.
  • Total SP = ₹ 1140 + ₹ 1320 = ₹ 2460.

Since total SP > total CP , A profit of ₹ ( 2460 - 2400 ) or ₹60 has been made ..

<h3>Hope this helps you :)</h3>
4 0
3 years ago
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