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xenn [34]
3 years ago
10

Click the photo to find the measure of each interior angle of the regular polygon

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0
<h3>Answer:  120 degrees</h3>

==============================================

Work Shown:

n = number of sides = 6

i = measure of interior angle

i = 180(n-2)/n

i = 180(6-2)/6

i = 180(4)/6

i = 720/6

i = 120

Each interior angle of this regular hexagon is 120 degrees.

-----------------

Alternative Approach:

E = exterior angle

E = 360/n

E = 360/6

E = 60

Each exterior angle of this regular hexagon is 60 degrees

i+E = 180

i = 180-E

i = 180-60

i = 120

We get the same answer.

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Which of the following functions is graphed below?
mrs_skeptik [129]

Step-by-step explanation:

For y = x^3 - 4 when x = 0, y = -4.

For y = x^2 + 3 when x = 0, y = 3.

Looking at the graph, the y-intercept of the function is below 0. Hence the bottom part is from x^3 - 4 and the top is from x^2 + 3.

The bottom part has a dark circle, which means when x = 1 it belongs to x^3 - 4.

Hence the answer is D.

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3 years ago
Tommy has a pet monkey. Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana th
Licemer1 [7]

Answer:

Step-by-step explanation:

Let x represent the number of bananas that Tommy eats.

Let y represent the total number of pieces of fruit that the monkey eats.

Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana that tommy eats. This means that the number of bananas that the monkey eats is 2x. The expression for the total number of fruits eaten by the monkey becomes

y = 2x + 4

4 0
3 years ago
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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

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inn [45]

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It's important to know that the proper way to find the distance here is by subtraction, we need to subtract the final points and the initial point. In math, such subtraction is called "differential" or "variation", just a fancy name.

\Delta=\frac{1}{2}-(-2)=\frac{1}{2}+2=0.5+2=2.5

<h2>Therefore, the distance from O to B is 2.5 units.</h2>
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15.9687194227 units between the 2 points

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