Answer:
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
p+/-z√(p(1-p)/n)
p+/-M.E
Given that;
M.E = margin of error
Proportion p = 52% = 0.52
Number of samples n = 700
Confidence interval = 95%
z value (at 95% confidence) = 1.96
Substituting the values we have;
0.52 +/- 1.96√(0.52(1-0.52)/700)
0.52 +/- 1.96(0.0189)
0.52 +/- 0.0370
( 0.4830, 0.5570)
The 95% confidence interval estimate of the true population proportion of U.S. employers that were likely to require higher employee contributions for health care coverage is 0.52 +/- 0.0370
= (0.4830, 0.5570)
The margin of error M.E = 0.0370
Yes.
4 cups of flour/3 cups of milk= 1.33 flour/milk
2 cups of flour/ 1.5 cups of milk= 1.33 flour/milk
As you can see, these are the same ratios.
Answer:
157,500
Step-by-step explanation:
45,000 x 3.5$= 157,500
Lolz i' wrong prolly cuh so my bad g
Answer:
Its 2
Step-by-step explanation:
1+1=2
The segments AE, EC, AD and DB are in proportion.
Therefore we have the equation:

AE = 4ft, AD = 8ft and BD = 2ft. Substitute:
<em>multiply both sides by 2</em>
