3 years ago

Please help I really need Zoom in so it won’t be blurry

Mathematics

1 answer:

garri49 [273]3 years ago

3 0

Answer:

25.

Step-by-step explanation:

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PLEASE LOOK AT THIS multiple choice, thanks.

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Answer:

The answer should be y= -2x + 8

Step-by-step explanation:

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3 years ago

-1/2 -8/15 which on is bigger

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-1/2 is bigger than -8/15

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the initial population of a town is 3200 grows with a doubling time of 10 yrs what will the population be in 12yrs

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I think 6464

Step-by-step explanation:

I wish you luck on this assignment:P:D

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A recipe calls for 1/4 of flour. Carter only has a measuring cup that holds 1/8 cup. How can Carter measure the flour he needs f

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Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

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3 years ago

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