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djverab [1.8K]
3 years ago
6

Write an appropriate direct variation equation if y = 18 when x = 2

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

y=9x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem we have

y=18 when x=2

Find the value of the constant of proportionality k

k=\frac{y}{x} ----> k=\frac{18}{2}=9

therefore

The equation is equal to

y=9x

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faltersainse [42]

I’m very sorry but I don’t understand

Step-by-step explanation:

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3 years ago
Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati
Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)


\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9


\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill

7 0
3 years ago
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
MaRussiya [10]

Answer:

the figure could be a rhombus because the 2 lines of symmetry bisect the angles

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

No.

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