Please give me brainleist. :)
Answer:
2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.
2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.
2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.
2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.
3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.
3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.
3c. It would shift to the right in order to get rid of the excess form products from it.
3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.
4a. K=[N2O4(g0] / [NO2(g)]2
4b. (Below)
K=[N2O4(g)] / [NO2(g)]2
0.4 / 0.5(2)
0.4/0.25 = 1.6
Keq= 1.6
Answer:
47.8 moles of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O
Finally, we shall determine the number of mole of water, H₂O, produced by the reaction of 23.9 moles of O₂. This can be obtained as follow:
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O.
Therefore, 23.9 moles of O₂ will react to produce = 23.9 × 2 = 47.8 moles of H₂O.
Thus, 47.8 moles of H₂O were obtained from the reaction.
Answer:
the pressure at c = 0.27 atm
Explanation:
Given that:
number of moles (n) = 1.0 moles
Value of gamma in the monoatomic gas (γ) = 5/3
During an isothermal expansion, the volume at b is = 2.5 times the volume at a ; this implies that:
∴ To calculate the pressure at c from a; the process is adiabatic compression; so we apply:
![\frac{P_c}{P_a}=[\frac{V_a}{V_c}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7BP_a%7D%3D%5B%5Cfrac%7BV_a%7D%7BV_c%7D%5D%5E%7B%282%2F3%29)
![\frac{P_c}{1.0 atm}=[\frac{1}{2.5}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7B1.0%20atm%7D%3D%5B%5Cfrac%7B1%7D%7B2.5%7D%5D%5E%7B%282%2F3%29)
Thus, the pressure at c = 0.27 atm
The lanthanides and actinides are separated from the rest of the periodic table, usually appearing as separate rows at the bottom. The reason for this placement has to do with the electron configurations of these elements.
Answer:
A. The sum of the voltages of the half-reactions is positive.
Explanation:
correct on a p e x
