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oksian1 [2.3K]
3 years ago
9

Write the equation of the​ line, with the given​ properties, in​ slope-intercept form.

Mathematics
1 answer:
hoa [83]3 years ago
8 0

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(9-3)/(4-2)

m=6/2=3

y=mx+c

y=3x+c

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Read 2 more answers
What are the types of roots of the equation below? x^4 - 81 = 0
blsea [12.9K]
Your answer is B, two complex roots and two real roots.

By factoring the original equation(which is a difference of two squares), you get:
x^{4}-81=0\\(x^{2}-9)(x^{2}+9)=0

Because first root is also a difference of two squares, it factors into x - 3 and x +3, your two real roots.
When you factor the second root, the roots are x - 3i and x + 3i.

To prove this, let's multiply them back together:
[(x-3)(x+3)][(x-3i)(x+3i)]=0\\\\(x^{2}+3x-3x-9)(x^{2}+3xi-3xi-9i^{2})=0\\\\(x^{2}+0x-9)(x^{2}+0xi-9(-1))=0\\\\(x^{2}-9)(x^{2}+9)=0\\\\x^{4}+9x^{2}-9x^{2}-81=0\\\\x^{4}-81=0

We reached the equation we started with, so that means that the roots are:
x + 3,
x - 3,
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x - 3i,
two of which are real and two are complex.
7 0
3 years ago
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