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3 years ago

Write the equation of the line, with the given properties, in slope-intercept form.

Mathematics

1 answer:

hoa [83]3 years ago

8 0

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(9-3)/(4-2)

m=6/2=3

y=mx+c

y=3x+c

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The bearing of ships A and B from a port P arev225 and 116 respectively ship A is 3.91 from ship B on a bearing of 258 calculate

pashok25 [27]

Answer:

2.55

Step-by-step explanation:

Draw a picture of the triangle formed by points P, A, and B. The angle of the line from P to A is 225°. The angle of the line from P to B is 116°. The angle of the line from B to A is 258°, and the length of the line is 3.91.

The easiest way to solve this is by first finding the angle of the line from B to P. Using interior angles, we can show that this is 180° − 116° = 64°.

Next, we can show that:

∠APB = 225° − 116° = 109°

∠ABP = 360° − (258° + 64°) = 38°

Finally, we can use law of sines to find AP.

AP / sin 38° = 3.91 / sin 109°

AP = 2.55

4 0

3 years ago

Brian drove 120 miles at speed of 60 miles per hour. He drove the same distance back home at average speed of 40 miles per hour.

Solnce55 [7]

I dont really understand the question,

5 0

3 years ago

ben says that an array with 2 ross and 5 columns has 8 items. is this reasonable? Explain why or why not?

IgorLugansk [536]

This is not reasonable because
$2 \times 5 = 10 \\$

5 0

3 years ago

If 8 is added to twice a number and this sum is multiplied by 5, the result is the same as if the number is multiplied by negat

Naily [24]

(8+2x) -> If 8 is added to twice a number (x)
5*(8+2x) -> and this sum is multiplied by 5
5*(8+2x)=x*(-28)+2 -><span>the result is the same as if the number is multiplied by negative −28 and 2 is added to the product.

Simplifying the equations on both sides would give
40+10x=-28x+2 transpose -28 to the left side and 40 to the right side
28x+10x=2-40
38x=-38
x=-1</span>

3 0

3 years ago

What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>

mina [271]

Answer:

$\frac{-6+\sqrt{78} }{6}$ and $\frac{-6-\sqrt{78} }{6}$

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

$\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

$\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6}, \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}$

= $\frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}$

= $\frac{-6+\sqrt{78} }{6}$ and $\frac{-6-\sqrt{78} }{6}$

Hence, x= $\frac{-6+\sqrt{78} }{6}$

and x= $\frac{-6-\sqrt{78} }{6}$

(Answer)

9 0

4 years ago

Write the equation of the​ line, with the given​ properties, in​ slope-intercept form.

Write the equation of the line, with the given properties, in slope-intercept form.