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ivanzaharov [21]
3 years ago
5

Help need answer fast

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

A hope this helps

Step-by-step explanation:

hopes this helps bye

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Ten children ran a lemonade stand all summer. They made $485. If they split the money evenly, how much will
Dmitrij [34]

Answer:

$48.5

Step-by-step explanation:

There are ten children and the total made is $485. So:

485/10 = $48.5

3 0
3 years ago
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A researcher tests the braking distances of several cars. The braking distance from 60 miles per hour to a complete stop on dry
ZanzabumX [31]

Answer:

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.

This means that \mu = 129, \sigma = 5.18

What is the longest braking distance one of these cars could have and still be in the bottom 1%?

This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.

Z = \frac{X - \mu}{\sigma}

-2.327 = \frac{X - 129}{5.18}

X - 129 = -2.327*5.18

X = 116.94

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

5 0
3 years ago
Help with question pls!! Marking brainliest
weeeeeb [17]

Answer:

The answer is C. (5, 1)

Step-by-step explanation:

It takes two vertical downward swoops and one horizontal leftward swoop to get from point G to point F (3 swoops total). If point H was placed at (5, 1), it would take two horizontal leftward swoops and one vertical upward swoop to get from point H to point F (3 swoops total).

3 0
3 years ago
A certain forest covers an area of 3700 km² suppose that each year this area decreases by 8.25% what will the area be after six
Dafna11 [192]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the multiplier:

1 - 0.0825 = 0.9175

final = original x multiplier^n

n is the number of years

Substitute in the values:

final = 3700 x 0.9175^6

Solve:

final = 2207.182081

The area will be 2207.18 km^2

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Multiply the following and simplify, show all work<br><br> (3x^2+6x−6)(5x^2−3)
AnnyKZ [126]
<span>(3x^2+6x−6)(5x^2−3)
=15x^4 - 9x^2 + 30x^3 - 18x - 30x^2 + 18
</span>=15x^4 + 30x^3 - 39x^2 - 18x + 18
7 0
3 years ago
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