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3 years ago

Please help giving brainlest!! no links no unnecessary comments thank you :)

Mathematics

2 answers:

DochEvi [55]3 years ago

6 0

(7,3) it is I have to do 20 characteristics

seraphim [82]3 years ago

4 0

Answer:

Last point is at (7,-3)

Step-by-step explanation:

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Is it possoble for a system of linear equations to have no solution

Vera_Pavlovna [14]

Yes This Is Possible. This Would Happen If The Lines Never Intersected With Each Other. If This Was The Case, There Would Be No Point That Lies On Both Lines. Have A Great Day!

8 0

3 years ago

The point (0,0) is a solution to which of these inequalities?

Ipatiy [6.2K]

$y-7$

$(0)-7$

$0-7$

$-7$

-7 is lesser than -6.

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3 years ago

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Targe

Hatshy [7]

Idk math but I can sell come thru for that low

4 0

3 years ago

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

The formula for the volume sphere is V=4/3pie r^3 what is the formula solved for r?

oksian1 [2.3K]

Answer:

$r = \sqrt[3]{\frac{3V}{4 \pi}}$

Step-by-step explanation:

From the formula of volume of a sphere we have to isolate "r" on one side of the equation i.e. we have to make "r" the subject of the equation.

$V=\frac{4}{3} \pi r^{3}\\\\ \text{Multiplying both sides by 3/4 we get}\\\\\frac{3V}{4} = \pi r^{3}\\\\ \text{Dividing both sides by } \pi \\\\ \frac{3V}{4 \pi} = r^{3}\\\\\text{Takeing cube root of both sides}\\\\\sqrt[3]{\frac{3V}{4 \pi}} = r$

Therefore:

$r = \sqrt[3]{\frac{3V}{4 \pi}}$

3 0

3 years ago

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