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hjlf
3 years ago
12

A 100 foot wire is extended from the

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0
The angle that the wire makes with the ground is
36.869
8
o
.
36.8698
o
.
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How many 3/4s are in 1​
kirza4 [7]

Answer and Step-by-step explanation:

There is 1\frac{1}{3} \frac{3}{4} in the number 1.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0
3 years ago
Please solve will give BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINL
Mnenie [13.5K]

Answer:

3.4

Step-by-step explanation:

7 0
3 years ago
How does product (result) of (a-b)2 compare the product (a+b)
____ [38]
I'm assuming you mean (a-b)^2 : (a+b)^2

a^2 + b^2 cancel out leaving

-2ab versus +2ab

Therefore (a+b)^2 is +4ab greater.


5 0
3 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Jeremiah and Tristan work at a dry cleaners ironing shirts. Jeremiah can iron 35 shirts per hour, and Tristan can iron 20 shirts
laiz [17]

The number of hours Jeremiah ironed = 10 hours

The number of hours Tristan ironed = 7 hours

<u>Step-by-step explanation</u>:

  • Jeremiah can iron = 35 shirts per hour
  • Tristan can iron = 20 shirts per hour
  • Total work done by both = 490 shirts

Let 'x' be the number of hours Jeremiah ironed.

Let 'y' be the number of hours Tristan ironed.

x+y = 17   ------(1)

35x + 20y = 490  -------(2)

Multiply (1) by 20 and subtract (2) from (1),

 20x + 20y = 340

-(<u>35x + 20y = 490</u>)

 <u>-15x         = -150 </u>

x = 150/15

x = 10

Substitute x=10 in (1)

10+y = 17

y = 7

5 0
3 years ago
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