When Earth is tilted towards the Sun we receive BLANK Sun rays<br> A. Direct<br> B. Indirect

The height of a tree at time t is given by a twice-differentiable function H, where H(t) is measured in meters and t is measured

il63 [147K]

A) Use the mean value theorem.

$H'(6)\approx\dfrac{H(7)-H(5)}{7-5}=\dfrac{11-6}2=\dfrac52\text{ meters/year}$

Since $H(t)$ gives the tree's height in meters at time $t$ , the value of $H'(6)$ informs us how quickly the tree is growing exactly after 6 years have passed. (i.e. the instantaneous rate of change of the tree's height)

b) We use the mean value theorem again. Observe that $H(5)-H(3)=6-2=4$ , and that $5-3=2$ . By the MVT, there must be some $3$ such that

$H'(t)=\dfrac42=2$

c) The average height of the tree is given by the integral

$\displaystyle\frac1{10-2}\int_2^{10}H(t)\,\mathrm dt$

If you can remember the formula for the area of a trapezoid, then this is pretty easy to compute. With five data points, you end up with four trapezoids constructed by the four adjacent subintervals. The "bases" are given by the values of $H(t)$ at each pair of endpoints, and the "heights" are the lengths of the subintervals. For the integral itself, we get

$\dfrac{2+1.5}2(3-2)+\dfrac{6+2}2(5-3)+\dfrac{11+6}2(7-5)+\dfrac{15+11}2(10-7)=\dfrac{263}4$

So the average height of the tree (in meters) is

$\displaystyle\frac1{10-2}\int_2^{10}H(t)\,\mathrm dt\approx\frac{263}{32}$

d) When $G=50$ , the diameter of the base can be determined to be

$50=\dfrac{100x}{1+x}\implies x=1$

We're told that $\dfrac{\mathrm dx}{\mathrm dt}=0.03$ . $G$ is a function of $x$ which is in turn a function of $t$ , so when we differentiate, we use the chain rule:

$\dfrac{\mathrm dG}{\mathrm dt}=\dfrac{\mathrm dG}{\mathrm dx}\cdot\dfrac{\mathrm dx}{\mathrm dt}$

$\implies\dfrac{\mathrm dG}{\mathrm dt}=\dfrac{100}{(1+x)^2}\cdot\dfrac3{100}=\dfrac3{(1+x)^2}$

When the height of the tree is 50 meters, we found the diameter to be 1 meter, so at this point

$\dfrac{\mathrm dG}{\mathrm dt}=\dfrac34\text{ meters/year}$

4 0

2 years ago

Read 2 more answers

I need to know the answer asap

amm1812

subtract lowest time from highest time for each kind

129-29 = 100

320-210 = 110

the ranges are about the same but the times are higher for the dark chocolate

8 0

3 years ago

Help please. Screenshot included.

Alla [95]

The following information will help us with this problem:

$\sqrt[m]{x^n} = x^{\frac{n}{m}$

When we use that information in the context of this problem, we can find:

$\sqrt[4]{15^7} = 15^{\frac{7}{4}}$

Thus, a = 15, b = 7, and c = 4.

4 0

3 years ago

The

stiv31 [10]

Answer:

x = -3. Y = 12

Step-by-step explanation:

the answer is D

6 0

3 years ago

Find an expression which represents the difference when (2x − 6) is subtracted

Sloan [31]

Answer:

-2x + 8

Step-by-step explanation:

(2x - 6) is subtracted from (7 - 5).

First term that into an equation.

Because our first term is being subtracted from our second one, our equation is written as:

(7 - 5) - (2x - 6).

Simplify the first term by subtracting:

7 - 5 = 2

Now simplify the second term by multiplying 2x - 6 by -1 to get them out of the parenthesis. We do this because there is a negative sign in front of it.

-1 (2x - 6)

-2x + 6

Now our equation is:

2 - 2x + 6

Combine like terms:

2 + 6 = 8

So -2x + 8

(2x - 6) subtracted from (7 - 5) is -2x+8

4 0

10 months ago

When Earth is tilted towards the Sun we receive BLANK Sun rays A. Direct B. Indirect