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3 years ago

write the possible range of the measurement 214 ounces +1.2% round to the nearest hundredth if necessary

Mathematics

1 answer:

boyakko [2]3 years ago

3 0

9514 1404 393

Answer:

[211.43,216.57]

Step-by-step explanation:

1.2% of 214 is ...

0.012 × 214 = 2.568 ≈ 2.57 . . . . rounded to hundredths

Then the minimum possible value is ...

214 -2.57 = 211.43

and the maximum possible value is ...

214 +2.57 = 216.57

The range is 211.43 to 216.57.

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Solve each system of equations using the substitution method

boyakko [2]

Step-by-step explanation:

y=-3+5x

substitute y into equation 2

3x-8y=24

3x-8(-3+5x)=24

3x+24-40x=24

x=0

y=-3+5(0)

y=-3

(x,y)=(0,3)

7 0

3 years ago

Find the amount of the annuity. Round to the nearest cent.

jasenka [17]

FVAO=1500[((1+0.08)^(15)-1)/0.08]
FVAO=40728.17

8 0

3 years ago

Point A, located at (-11, - 7) on the coordinate plane, is reflected over the x-axis to form point B. Then point B is reflected

hram777 [196]

Answer:

Answer: B(-11,7) C(11,7)

Step-by-step explanation:

Reflections In The Coordinate Plane

Reflect over the x-axis:

When we reflect a point over the x-axis, the x-coordinate remains the same, but the y-coordinate is mapped to its opposite.

The reflection of the point (x,y) over the x-axis is the point (x,-y).

Reflect over the y-axis:

When reflecting a point over the y-axis, the y-coordinate remains the same, but the x-coordinate is mapped to its opposite (its sign is changed).

The reflection of the point (x,y) across the y-axis is the point (-x,y).

Point A is at (-11,-7). When reflected over the x-axis, it maps to Point B located at B(-11,7).

Point B is now reflected over the y-axis and maps to C(11,7).

Answer: B(-11,7) C(11,7)

6 0

3 years ago

40 POINTS!!

Elena-2011 [213]

I only know what in the picture which is the letter A

5 0

3 years ago

Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a s

Lilit [14]

Answer:

$y-2=\displaystyle -\frac{3}{4}(x-1)$

$y=\displaystyle -\frac{3}{4}x+\frac{11}{4}$

Step-by-step explanation:

Hi there!

Point-slope form: $y-y_1=m(x-x_1)$ where m is the slope of the line and $(x_1,y_1)$ is a given point

Given that the slope is -3/4, we can plug it into $y-y_1=m(x-x_1)$ as m:

$y-y_1=\displaystyle -\frac{3}{4}(x-x_1)$

We can also plug in the given point (1,2):

$y-2=\displaystyle -\frac{3}{4}(x-1)$

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate y:

$y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}$

I hope this helps!

8 0

2 years ago