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padilas [110]
3 years ago
12

6. (09.04 LC)

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

Given:

The quadratic equation is

y=6x^2-9x+22

To find:

The correct application of the quadratic formula.

Solution:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

We have,

y=6x^2-9x+22

Putting y=0, we get

6x^2-9x+22=0

Here, a=6,b=-9,c=22. Using the quadratic formula, we get

x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}

The correct application of the quadratic formula is x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}.

Note: The options are not in proper format.

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dlinn [17]

Answer:

See below

Step-by-step explanation:

The ratio of the secants is the same when set up as full length to external length.

Formula

MN/LN = QN/PN

Givens

LN = 22 + 14 = 36

MN = 14

PN = 32

QN = x

Solution

14/36 = x / (32)  Multiply both sides by 32

14*32 / 36 = x    Combine 14 and 32

448/36 = x         Divide by 36 and switch

x = 12.4

Answers

PN (External) = 13 is the closest answer

Length LN = 36

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