Question

6. (09.04 LC)

Answer 1

Given:

The quadratic equation is

$y=6x^2-9x+22$

To find:

The correct application of the quadratic formula.

Solution:

If a quadratic equation is $ax^2+bx+c=0$, then the quadratic formula is

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$y=6x^2-9x+22$

Putting $y=0$, we get

$6x^2-9x+22=0$

Here, $a=6,b=-9,c=22$. Using the quadratic formula, we get

$x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}$

The correct application of the quadratic formula is $x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}$.

Note: The options are not in proper format.