The maximum height of an object is the greatest height the object can reach. The maximum height the rocket reaches is 40.2 feet
<h3>Vertex form of an equation</h3>
The maximum height of an object is the greatest height the object can reach. Given the equation that represent the height of the rocket.
f(t) = -15t² + 48t
The maximum height of the rocket occur at the point where:
t = -b/2a
t = -48/2(-15)
t =48/30
t = 1.6secs
Substitute t = 1.6 into the function as shown:
f(1.6) = -15(1.6)² + 48(1.6)
f(1.6) = -38.4 + 76.8
f(1.6) = 40.2
Hence the maximum height the rocket reaches is 40.2 feet
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Answer:
the second one!
Step-by-step explanation:
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12 meters
Step-by-step explanation:
You have to use the inverse of the pythagorean theorem to do this so you do square root of (20x20-16x16) which is 12
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The slope is 8.000/2.000 = 4.000
The y-intercept is -7/1 = -7.00000
Step-by-step explanation:
^^
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- m=y2-y1 / x2-x1
- m= 5-2 / 9-0
- 3/9 =1/3
- y=mx+b
- 2=1/3(0)+b
- 2=b
- slope is 1/3
- y-intr is 2
Step-by-step explanation:
