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Serggg [28]
3 years ago
13

Charlie paid $17.00 For a video game if this amount included a 15% discount for ordering online what was the original price for

the video game
Mathematics
2 answers:
poizon [28]3 years ago
7 0
The 15% is 2.55 adding on 17.00 equals 19.55
Hope this helps :-)
Vesna [10]3 years ago
3 0
Okay so first we would do .15 for 15%. after this step is finished We would multiply .15 to 17.00 getting you 2.25


***If you like this answer please press the heart button rate me a 5 star and mark me Brainliest! Have a great day!***
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Tickets for the school concert were 3$ and 2$. If 245 tickets were sold for a total of $630, how much of each kind were sold?
Hatshy [7]
2x + 3y = 630
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Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
3 years ago
Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
fgiga [73]

Answer:

  • QN = 3√7
  • OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

  DQ = (3 units)·3 = 9 units

  KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

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  OI = √(16 -9)

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  QN = 3·OI = 3√7

8 0
3 years ago
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