<h3>
Answer: A. 9</h3>
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Explanation:
Draw in the segments AO and OC.
Triangle ABO is congruent to triangle CBO. We can prove this through the use of the HL theorem. HL stands for hypotenuse leg.
Since the triangles are congruent, this means the corresponding pieces AB and BC are the same length.
Then we can say:
AB+BC = AC .... segment addition postulate
AB+AB = AC .... plug in BC = AB
2*AB = AC
2*AB = 18
AB = 18/2 .... divide both sides by 2
AB = 9
In short, the chord AC is bisected by the perpendicular radius drawn in the diagram. So all we do is cut AC = 18 in half to get AB = 9.
Answer:
ligma
Step-by-step explanation:
a b c d
Answer:
A. one solution y=-3 and x=0
Step-by-step explanation:
7/10-3/10=2/5
3/10+1/10=2/5
Answers:
y = 50
angle AOB = 100
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Explanation:
Angle x is an inscribed angle that subtends or cuts off minor arc AB. This is the shortest distance from A to B along the circle's edge.
Angle y is also an inscribed angle that cuts off the same minor arc AB. Therefore, it is the same measure as angle x. We can drag point D anywhere you want, and angle y will still be an inscribed angle and still be the same measure as x.
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Point O is the center of the circle. This is because "circle O" is named by its center point.
Angle AOB is considered a central angle as its vertex point is the center of the circle.
Because AOB cuts off minor arc AB, and it's a central angle, it must be twice that of the inscribed angle that cuts off the same arc.
This is the inscribed angle theorem.
Using this theorem, we can say the following
central angle = 2*(inscribed angle)
angle AOB = 2*(angle x)
angle AOB = 2*50
angle AOB = 100 degrees
