Please help ASAP thanks :3

Savatey [412]

Let's do this using the process of elimination. Since you didn't include choice D, we can only use A, B, and C.
C: If we're finding the width of the patio, how is the thickness of the tiles going to help? C is wrong.
A: We already know the area (72), so how does knowing the perimeter help us? All we know using that information is that 2 pairs of numbers give us the perimeter & also multiply to get 72. But not which 2. A is wrong.
B: Pay more attention to the last part of B... "the length". Well, if we have the area (72), and we have the length, then we can do area/length-width to find the width. B is correct!

Don't forget to rate this answer the Brainliest!

4 0

3 years ago

Read 2 more answers

Over the course of a year, the population of squirrels in Seattle increased from 350000 to 434000.

dlinn [17]

Answer:

It is 24%

Step-by-step explanation:

3 0

3 years ago

Question 7(Multiple Choice Worth 1 points) (08.02 LC) Eva conducted a survey to find out the amount of time high schoolers spend

Lady bird [3.3K]

Answer:

The answer is "Option B".

Step-by-step explanation:

The difference between most time and also the least spending time on Internet surfing is 3 hours. Since we do not have charts for tables etc., only 3 can be used we need. A range is defined as the difference between the largest and the smallest amounts. The range between both the largest as well as the smallest is unique. In this reply, it tells us that the gap between most time and the fewer hours invested surfing the web is 3 hours.

In option A, it is wrong since the range has nothing to do with formulas. (Of course, the dividend with a divisor results in a quotient). Only subtraction and not division may be achieved.
In option C, when all surf for exactly one hour, it could take the largest time of 3 hours and 3 hours, the last time. Add it into the equation and the range of the data present would've been 0.
In option D, It is erroneous even as the range is not the mean, and the mean seems to be the average. We search for both the range, not the mean.