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Iteru [2.4K]
4 years ago
6

Help me out some one

Mathematics
1 answer:
Olegator [25]4 years ago
7 0
Y = mx + b is the slope-intercept form of the equation of a line,
where m = slope, and b = y-intercept.

In problems 1 and 3, your equations are written in the y= mx + b form, so you can read the slope and y-intercept directly.

1.
m = -5/2
b = -5

3.
m = -1
b = 3

5.
For problem 5, you need to solve for y to put the equation
in y = mx + b form. Then you can read m and b just like we did
for problems 1 and 3.

4x + 16y = 8

16y = -4x + 8

y = -4/16 x - 8/16

y = -1/4 x - 1/2

m = -1/4

b = -1/2
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(PLEASE ANSWER ASAP I JUST NEED TO KNOW IF I GOT THIS ONE CORRECT PLEASE EXPLAIN ALSO)
ella [17]

Hey there! I'm happy to help!

We have $100.75 to spend.

Each spool costs $3, and we have 24 spools.

3×24=72

Each glue costs $1 and we have 7 packages of glue.

7×1=7

We add up these expenses.

72+7=79

And we subtract from our total amount.

100.75-79=21.75

So, Joanna has $21.75 left after buying these things.

Have a wonderful day and keep on learning! :D

5 0
3 years ago
Read 2 more answers
Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.
Butoxors [25]

Answer:

the answers are all bold below

Step-by-step explanation:

Triangle ABC is an equilateral triangle with side lengths labeled a, b, and c.

Triangle A B C is an equilateral triangle. The length of side A B is c, the length of B C is a, and the length of A C is b.

Trigonometric area formula: Area = One-half a b sine (C)

Which expressions represent the area of triangle ABC? Select three options.

a c sine (60 degrees)

One-half b c sine (60 degrees)

One-half a squared sine (60 degrees)

StartFraction a squared b sine (60 degrees) Over 2 EndFraction

StartFraction a b sine (60 degrees) Over 2 EndFraction

6 0
3 years ago
Read 2 more answers
Which of the following properly describe "slope"? Select all that apply
son4ous [18]
Boxes 1 and 4 apply :)
8 0
3 years ago
Find an equation for the line tangent to the curve at the point defined by the given value of d²y/dx².​
mars1129 [50]

Answer:

Step-by-step explanation:

Given:

x = 2cost,

t = (1/2)arccosx

y = 2sint

dy/dx = dy/dt . dt/dx

dy/dt = 2cost

dt/dx = -1/√(1 - x²)

dy/dx = -2cost/√(1 - x²)

Differentiate again to obtain d²y/dx²

d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)

At t = π/4, we have

(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)

4 0
3 years ago
Find the area of a circle with a circumference of 6.28 unitesz
Anni [7]

Answer:

3.14 square units

Step-by-step explanation:

Circumference of a circle = 2πr

2πr = 6.28

r = 6.28/2π

r = 3.142/π

Area of a circle = πr^2

slot in the value of r

Area of the circle = π( 3.142/π)^2

               "              = π(9.87/ π^2)

                "             = 9.87/π

π = 3.14

Area of a circle = 9.867/ (3.14)

              "            = 3.14 square units

                     

8 0
3 years ago
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