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Pie
3 years ago
10

The difference between the record high and low temperatures in Daytona Beach, Florida, is 87°F. The

Mathematics
2 answers:
lara [203]3 years ago
7 0

Answer:

the record low temperature is 15 degrees RESPECTFULLY BOZO WHAT ARE YOU STOOPID WORD TO MY MOTHA SON YOU IS DEAD TO ME RESPECTFULLY

MissTica3 years ago
4 0
The record low temperature is 15 degrees Fahrenheit
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X + 5y = -2
natita [175]

Answer:

the answer is -1. please thank my answer please and thank you

3 0
4 years ago
Determine the effect on the balance sheet after the following transaction.
Maslowich
The transaction of this is
Cash. Increase by 750
3 0
3 years ago
Read 2 more answers
find the coordinates of the vertex of the following parabola algebraically. write your answer as an (x,y) point..y=x²+9
Alexandra [31]

Explanation:

using the parabola formula:

y = a(x-h)² + k²

vertex = (h, k)

We are given a parebola equation of: y = x²+9

comparing both equations to get the vertex:

y = y

a = 1

(x-h)² = x²

x² = (x + 0)²

(x-h)² = (x + 0)²

h = 0

+k = +9

k = 9

The vertex of the parabola as (x, y): (0, 9)

3 0
2 years ago
What is the value of x in the triangle? A. 21 B. 10 C. 7 D. 7√3
enyata [817]
A

Working:
Tan(angle)=opposite/adjacent
Tan60 = x/7root3
x=7root3 x Tan60
Enter in calculator
x=21
4 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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