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tatiyna
3 years ago
7

Suppose that the cost of producing x tablets is defined by c(x)= 200 + 10x + 0.2x squared* where x represents the number if tabl

ets produced. The graph below represents the function.

Mathematics
1 answer:
sammy [17]3 years ago
5 0

we are given

C(x)=200+10x+0.2x^2

part-A:

Since, x is number of tablets

C(x) is cost of producing x tablets

so, vertical box is C(x)

so, we write in vertical box is "cost of producing x tablets"

Horizontal box is x

so, we write in horizontal box is "number of tablets"

part-B:

we have to find average on [a,b]

we can use formula

\frac{C(b)-C(a)}{b-a}

we are given point as

a: (15 , 395)

a=15 and C(15)=395

b: (20, 480)

b=20 , C(20)=480

now, we can plug values

=\frac{480-395}{20-15}

=17...........Answer

part-c:

we have to find average on [b,c]

we can use formula

\frac{C(c)-C(b)}{c-b}

we are given point as

b: (20, 480)

b=20 , C(20)=480

c:(25,575)

c=25 , C(c)=575

now, we can plug values

=\frac{575-480}{25-20}

=19..............Answer


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A necklace and earrings cost $144. Six necklaces and five pairs of earrings cost $825
hram777 [196]

Step-by-step explanation:

let necklace : x

let earrings : y

x+y=144 -1st eqn

6x+5y=825 -2nd eqn

y=144-X -3rd eqn

substitute eqn into 2nd eqn

6x+5(144-x)= 825

6x +720-5X =825 (expanded)

X = 825-720

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substitute "X=105" into 1st eqn

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6 0
2 years ago
A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi
inessss [21]

Answer:

\frac{1429}{120} or 11\frac{109}{120}

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)

x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)

x = \frac{1}{120}(40+30+24+15+840)

x = \frac{1}{120}(949)

x = \frac{949}{120}

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = \frac{949}{120}+4

Original number of peaches = \frac{949+4\times 120}{120}

Original number of peaches = \frac{949+480}{120}

Original number of peaches = \frac{1429}{120}

Original number of peaches = 11\frac{109}{120}

Therefore the original number of peaches in the basket is \frac{1429}{120} or 11\frac{109}{120}

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