I could use the points so if you want to mark this as helpful that would be cool :)
Answer:
Is this for a Trig class? just wondering
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
we want to find the Hypotenuse (Hyp) and are given an angle and the adjacent side (adj) sooo use CAH , b/c it has all of the pieces
Cos(37) = Adj / Hyp
Cos(37) = 11 / Hyp
swap Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra
Hyp = 11 / Cos(37)
now solve with your handy TI 83 / 84 / 89 calculator :) if you don't have one go get one . :D get the 89 if you are going into engineering classes... the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )
Hyp = 13.77349...
Hyp = 13.8 ( rounded to nearest 10th ) :)
Answer:
<u>The first picture</u>
Two angles and the included side of ΔBOY are congruent to corresponding parts of ΔMAN
<u>The second picture</u>
We can see parallel segments and transversals forming 3 congruent angles in both triangles but this is not enough to state the triangles are congruent.
BA ∩ LC = K is not a midsegment.
With the info we have we can only state that the triangles are similar but not congruent.
Answer:All even numbers greater than two are composite numbers. This is because they are all evenly divisible by themselves and by 1, and since they are.
Step-by-step explanation: