Answer:
Option D. LN=64 units
Step-by-step explanation:
step 1
Find the value of x
we know that
LN=LM+MN -----> equation A
we have
LN=12x+16
LM=10x+8
MN=5x-4
substitute the values in the equation A
12x+16=(10x+8)+(5x-4)
Solve for x
12x+16=15x+4
15x-12x=16-4
3x=12
x=4
step 2
Find the value of LN
LN=12x+16
LN=12(4)+16=64 units
A rhombus has two sets of parallel sides. A rhombus has two pairs of angles
Hello!
When doing Sine, Cosine and Tangent the sides of the triangle tell you what to do
The hypotenuse is H
The bottom side is A
The Straight up and down side is O
For Sine you do O / H
For Cosine you do A / H
For Tangent you do O/ A
Put in the values you Sine
Sin A = 5/ 13
Put in the values for Cosine
Cos A = 12/ 13
The answer is A) Sin A = 5/ 13, cos A = 12/ 13
Hope this helps!
((-4x^3)(y^4))^-3
--------------------------
(2xy^4)^-4
16x^4y^16
=------------------------
-64x^9y^12
-16y^4
=------------------------
64x^5
-y
=------------------------
4x^5
So the final answer is:
-y^4
-------
4x^5
(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)
Hopefully this was helpful in some way.
Answer:
See below in bold.
Step-by-step explanation:
(x - 1)(x^2 + 1)
= x(x^2 + 1) - 1(x^2 + 1)
= x^3 + x - x^2 - 1
= x^3 - x^2 - x - 1.
Leading coefficient = 1.
Constant term = -1.
Degree = 3. (because of the x^3).
