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Olin [163]
3 years ago
6

Table Setting in any occasion can add to the beauty and significance of the event. It may

Computers and Technology
1 answer:
Rudiy273 years ago
7 0

Answer:

HMMMM IM THINKING HMMMMM

Explanation:

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Consider a physical transmission medium of capacity C bits/sec between two stations that have I bits of information sent/receive
levacccp [35]

Answer:

Check the explanation

Explanation:

when calculating the total time to send the I bits of information or The packet delivery time or latency which can be said to be the amount of time from when the first bit leaves the point of transmission until the last is received. When it comes to a physical link, it can be computed or determined as: Packet delivery time = Transmission time + Propagation delay.

Kindly check the attached image below to get the step by step explanation to the above question.

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Referat noaptea la școala cu sfârșit de groază​
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A graphic design student is putting the finishing touches on her PowerPoint presentation for her speech. She is carefully analyz
elixir [45]

Answer:

Balance

Explanation:

Maintaining balance entails making sure things are in the right place, in the right proportion and maintaining a stable look and stand.

Maintaining a balance on a power point presentation entails that one considers these; ths one should carefully analyse how the different images go together and ensure that the positioning of elements within the images helps to make the individuals point and is pleasing to view.

This can be tasking but worth every effort put in to achieve such, because it will make your presentation to be easier to explain and better understood.

7 0
2 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
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