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nordsb [41]
2 years ago
7

You deposit $500 in an account that earns 4% simple annual interest entrance and each year is added to the principal to create a

new principal find the total amount in your account after each year for three years
Mathematics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

first year $20 second year $20.80 Third year $21.63

Step-by-step explanation: This is for an extra money per year so after the first year that is how much extra money he gets every year.

You might be interested in
When a constant force acts
yan [13]

Answer:

25

Step-by-step explanation:

First expression: A= k/M

when A = 15 and M = 5, k = A×M = 75

therefore, when M = 4, A = 75/3 = 25

7 0
2 years ago
5. Natalie has a pound bag of 1/8 pound bag of gummy worms, a 1/2 pound bag of twizzlers, and a 2/3 pound bag of chocolate. How
AveGali [126]

Step-by-step explanation:

1. Add all the different candies together

1/8 + 1/2 + 2/3=

2. Find the lowest common multiple of all the denominators

All the denominators can evenly multiply to 24 so 24 is the Lowest Common Denominator.

3. Multiply to make all the denominators 24

8x3=24 2x12=24 3x8=24

4. Whatever you did to the denominators, do the same thing to the numerators of that specific denominator.

1x3/8x3 1x12/2x12 2x8/3x8

5. Now that the denominators are the same for all the fractions, add all the numerators together.

3/24 + 12/24 + 16/24

3+12+16= 31

ANSWER: Natalie had 31/24 pounds of candy in all

Note: The decimal form is 1.292 pounds

7 0
3 years ago
Can an answer to an equation be a decimal?
sesenic [268]

Answer:

Yes

Step-by-step explanation:

An answer to an equation can be a decimal!

-Please mark as brainliest!-

-Hope this helps!-

-Good luck!-

6 0
4 years ago
Read 2 more answers
For a craft activity at a daycare, each child will need 1.75 yards of ribbon and 2.8 yards of fabric. There are 25 yards of ribb
devlian [24]
25/1.75 is approximately 14
30/2.8 is about 10. Because the kids need BOTH ribbon and fabric, only 10 can participate because that's all the fabric available
8 0
3 years ago
Read 2 more answers
In matrix multiplication, such as AB=C, the columns of B form the rows of C. why is this?
Gnesinka [82]
Let's work with 2-by-2 matrices so we're on the same page. The ideas will work for any appropriate matrices.

From the rule of matrix multiplication, we see:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right] = \left[\begin{array}{cc} a_{11}b_{11} + a_{12}b_{21} & a_{11}b_{12} + a_{12}b_{22} \\ a_{21}b_{11} + a_{22}b_{21} & a_{21}b_{12} + a_{22} b_{22} \end{array}\right]
As you noted, we see the columns of B contributing to the rows of C. The question is, why would we ever have defined matrix multiplication this way?

Here's a nontraditional way of feeling this connection. We can define matrix multiplication as "adding multiplication tables." A multiplication table is made by starting with a column and a row. For example,
\begin{array}{ccc} {} & 1 & 2 \\ 1 & {} & {} \\ 2 & {} & {} \end{array}
We then fill this table in by multiplying the row and column entries:
\begin{array}{ccc} {} & [1] & [2] \\ 1| &1 & 2 \\ 2| & 2 &4 \end{array}
It's then reasonable to say that given two matrices A and B, we can construct multiplication tables by taking the columns of A and pairing them with the rows of B:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right]

= \begin{array}{cc} {} & \left[\begin{array}{cc} b_{11} & b_{12}\end{array} \right]\\ \left[\begin{array}{c} a_{11} \\ a_{21} \end{array} \right] \end{array} +\begin{array}{cc} {} & \left[\begin{array}{cc} b_{21} & b_{22}\end{array} \right]\\ \left[\begin{array}{c} a_{12} \\ a_{22} \end{array} \right] \end{array}

= \left[\begin{array}{cc} a_{11} b_{11} & a_{11} b_{12} \\ a_{21} b_{11} & a_{21} b_{12} \end{array} \right] + \left[\begin{array}{cc} a_{12} b_{21} & a_{12} b_{22} \\ a_{22} b_{21} & a_{22} b_{22} \end{array} \right]

Adding these matrices together, we get the exact same expression as the traditional definition. 




5 0
3 years ago
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