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Sati [7]
2 years ago
13

What is the area of the parallelogram?

Mathematics
2 answers:
melomori [17]2 years ago
6 0

Answer:

4+4+15+15 that will show you the answer of the area

Elenna [48]2 years ago
3 0
Area of a parallelogram: A=bh
A = 4(15)
A= 60 inch squared

Hope this helps :)
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Somebody please help me
Elan Coil [88]
4x=6x-14

First isolate the variables onto one side and the numbers on the other so subtract 4x from both sides of the equation and add 14 to both sides of the equation to get 14=2x then you are going to want to completely isolate the variable so you divide 2 on both sides to get an answer of X=7
4 0
3 years ago
P-(2q+7) when p=10 and q=3​
tatuchka [14]

Answer:

-3

Step-by-step explanation:

6 0
3 years ago
Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.
Katarina [22]

Answer:

\dfrac{5}{6}

Step-by-step explanation:

When two dice are rolled, the sample space is

\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: (4,6),\ (5,5),\ (6,4)

11: (5,6),\ (6,5)

12: (6,6)

In total, 6 outcomes.

The probability that the sum is 10 or greater is

P(A)=\dfrac{6}{36}=\dfrac{1}{6}

Use the complement rule to find that the probability that the sum of the dice is less than 10:

P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}

6 0
3 years ago
Solve for Y<br> -2x + Y = 3<br><br> I need it broken down in steps
MA_775_DIABLO [31]
Step 1: set up equation 
-2x+y=3
Step 2: add 2x to both sides
-2x+y=3
+2x     +2x
<u>
y=3+2x</u>


Hope this helps :)
4 0
3 years ago
Read 2 more answers
I am loosing soo much of my points by doing this I was at 102 now I am at 40 please answer these correctly
kupik [55]

Answer:

C

Step-by-step explanation:

If we know that x is greater than or equal to 4, then we should substitute 4 in place of x in each possible solution.

A 4 + 3 ≥ 1   True, it's greater, but it can't be equal to.

B 3(4) ≥ 1     It's greater once again, can't be equal to.

C 4 - 3 ≥ 1     If x can also be greater than 4, then it works both ways. Equal and greater than.

3 0
3 years ago
Read 2 more answers
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