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3 years ago

10) The line FG is a diameter of the circle with centre C (6, 1). Given F is (2.-3), find the coordinates of G.

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

Answer:

Coordinates of the endpoint g is (10,5)

Step-by-step explanation:

The coordinates of a midpoint can be found using the formula;

(x,y) = (x1 + x2)/2 , (y1 + y2)/2

In this case, we have the mid point but we want to get the end point

Thus;

(6,1) = (x1 + 2)/2 , (y1-3)/2

x1 + 2 = 2(6)

x1 + 2 = 12

x1 = 12-2

x1 = 10

y1 - 3 = 2(1)

y1 -3 = 2

y1 = 2 + 3

y1 = 5

The coordinates of G are (10,5)

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Step-by-step explanation:

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3 years ago

The line AB has midpoint (-2, 4).<br>A has coordinates (3,-2).<br>Find the coordinates of B.

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Answer: B(8, -8 )

Step-by-step explanation: The formula for calculating mid - point between two points is given as :

M = ( $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$ )

The mid point has been given from the question .

$x_{1}$ = -2

$x_{2}$ = ?

$y_{1}$ = 4

$y_{2}$ = ?

substituting into the formula , we have

(3 , - 2 ) = ( $\frac{-2+x_{2}}{2}$ , $\frac{4+y_{2}}{2}$ )

Equating x -component to x and y component to y , we have

3 = $\frac{-2+x_{2}}{2}$

cross multiplying , we have

6 = -2 + $x_{2}$

Therefore:

$x_{2}$ = 8

Also , equating y component to y , we have

-2 = $\frac{4+y_{2}}{2}$

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$y_{2}$ = -8

Therefore :

$x_{2}$ = 8

$y_{2}$ = -8

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10) The line FG is a diameter of the circle with centre C (6, 1). Given F is (2.-3), find the coordinates of G.​

10) The line FG is a diameter of the circle with centre C (6, 1). Given F is (2.-3), find the coordinates of G.