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aksik [14]
3 years ago
8

Find the Retail Price. Given: Original Price: $60; Markup: 18%

Mathematics
2 answers:
inessss [21]3 years ago
8 0

Answer:

$70.80

Step-by-step explanation:

solniwko [45]3 years ago
3 0

Answer:

$2.88

Step-by-step explanation:

Hey hoped I helped! Have an amazing day and consider marking this brainliest if you do thank you in advanced! Merry Christmas!

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Which sentence uses coordinate adjectives?
Salsk061 [2.6K]
The correct answer should be A) because the adjectives are water and ice and they're describing the glass.
6 0
3 years ago
Use the figure at the right to answer the following questions.
Lisa [10]

<h3><u>Answers:</u></h3>

1. Name all the line segments.

<u>Ans.</u><u> </u> PL, LA, AY, YS,

2. How many line segments were formed?

<u>Ans.</u><u> </u> 4 (four)

3. Name all rays

<u>Ans.</u><u> </u>AM, AN

4. How many rays were formed?

<u>Ans.</u> 2 (two)

5. Name the opposite rays :

<u>Ans.</u><u> </u>AM, AN

6. Is point A between MN ?

<u>Ans.</u><u> </u>Yes

7. Find the line segments and rays formed by 5 points.

<u>Ans.</u><u> </u>

  • Line segment = PL, LA, AY, YS,
  • Rays = AM, AN

<h3>Hope it helps you.</h3>
7 0
2 years ago
The weight of an organ adult male has a bell-shaped distribution with a mean of 330
aleksley [76]

Answer:

b) 50%

Step-by-step explanation:

give brainliest plz

7 0
2 years ago
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
3 years ago
Please help!!!! 270 is what percent of 90?
Nana76 [90]
Do you mean 90 is what percent of 270 cause if you do the. It’s 75% ifnyku actually mean it like that then 175%
4 0
3 years ago
Read 2 more answers
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