All categories

2 years ago

Find the Retail Price. Given: Original Price: $60; Markup: 18%

Mathematics

2 answers:

inessss [21]2 years ago

8 0

Answer:

$70.80

Step-by-step explanation:

solniwko [45]2 years ago

3 0

Answer:

$2.88

Step-by-step explanation:

Hey hoped I helped! Have an amazing day and consider marking this brainliest if you do thank you in advanced! Merry Christmas!

You might be interested in

A triangle has an area of 36 cm². The base and height are scaled by a factor of 5.

ahrayia [7]

Triangle Area = .5 * (base * height)
36 = (base * height) / 2
So let's say base = 9 height 8
If base and height are scaled by a factor if 5 than
base = 45 height 40 and
area = .5 * (45 * 40)
area = 900

Basically, the area increases by a factor of 25.
The base increases by 5 and the height increases by 5 so the area increases by 5*5 = 25

4 0

3 years ago

Prove whether the following inferences are valid using the long or short truth table method. If they are invalid, give the count

bezimeni [28]

Answer:

Step-by-step explanation:

7 0

2 years ago

2.789 in word form and in expanded form

mylen [45]

Word form:
Two and seven hundred eighty-nine thousandths

Expanded form:

2

+ 0.7

+ 0.08

+ 0.009

5 0

3 years ago

Read 2 more answers

During a relay, Natasha swam 0.8 km and Kevin swam 500 m. How many meters did they swim in total?

Savatey [412]

I wanna say its 16
(not 100% sure)

6 0

3 years ago

Read 2 more answers

The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

The probability of selecting a desktop is = $P(Desktop) = p_{Y} = \frac{5}{9}$

Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

$P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}$

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0

2 years ago