When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula
for
0=ax²+bx+c

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so



it has to be a positive time
so it will hit the ground after

seconds
Answer:
The correct answer is B
Step-by-step explanation:
If we plug in x=10 to the equation, we get y=47
Since y is positive, A is not an counterexample
Since y is a function of x, C is not an counterexample
Since the graph of y is a parabola, D is not an counterexample
Hope this helped and mark as brainliest!
Answer:
Option 4
Step-by-step explanation:

Answer:
57°
Step-by-step explanation:
180-56=114
114÷2=57
Step-by-step explanation:
A. 2(x+4)=2x+8
=G
B. 3(2x-1)=6x-3
=I
C. 4(x+2)=4x+8
=J
D. 2(x+3)=2x+6
=K
E. 3(4x+1)=12x+3
=H
A - G
B - I
C - J
D - K
E - H
<em><u>H</u></em><em><u>O</u></em><em><u>P</u></em><em><u>E</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>H</u></em><em><u>E</u></em><em><u>L</u></em><em><u>P</u></em>