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notsponge [240]
3 years ago
12

HELP ME PLEASE ASAP! Rewrite using a single positive exponent (6^-3)^-9

Mathematics
1 answer:
sammy [17]3 years ago
7 0
1/(6^-3)^9 hope this helps :)
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Algebra question, any help is appreciated
Solnce55 [7]
Your answer here would be B
5 0
3 years ago
Read 2 more answers
Simplify.
Dominik [7]

Simplify: [{y^(2/7)}/{y^(1/2)}]

Since, [{a^(p/q)}/{a^(r/s)}] = a^{(p/q)-(r/s)}

Where,

  • a = p
  • p/q = 2/7 and
  • r/s = 1/2

so,

= y^{(2/7)-(1/2)}

Take the LCM of denominator i.e.,2 & 7 is 14.

= y^{(2*2 - 1*7)/14}

= y^{(4-7)/14}

= y^(-3/14) Ans.

<u>read</u><u> </u><u>more similar</u><u> questions</u><u>:</u> Which equation can be simplified to find the inverse of y = x2 – 7? a: x=y ^ 2 - 1/7 b: 1/x = y^2 - 7 c: x = y^2 – 7 d: –x = y^2 – 7..

brainly.com/question/2396514?referrer

6 0
2 years ago
If f(x) = 2x-7 and g(x)= x2-5, find g[f(5)]
Georgia [21]

Answer:

4x-12

Step-by-step explanation:

2x-5[2x-7(5)}=2x+2x-7-5

4x-12

negative integers are added to each other

4 0
3 years ago
Read 2 more answers
When Mr. Desrosiers was younger, he collected Superman comic books and would save his allowance money to purchase more comic boo
Lemur [1.5K]

Answer:

thirty five comic books

8 0
3 years ago
Write the linear system:
notsponge [240]

Answer:

(See explanation for further details).

Step-by-step explanation:

C) The linear system is:

(-1)^{2} \cdot a + (-1)\cdot b + c = 5

c = - 4

(4)^{2}\cdot a + (4)\cdot b + c = 0

After some algebraic handling:

a - b + c = 5

c = -4

16\cdot a + 4\cdot b + c = 0

By direct substitution:

a - b - 4 = 5

16\cdot a + 4\cdot b - 4 = 0

a - b = 9

4\cdot a + b = 1

a = 9 + b

4\cdot (9+b)+b = 1

36 + 5\cdot b = 1

5\cdot b = -35

b = -7

a = 2

D) The parameter values are: a = 2, b = -7, c = -4

E) The quadratic equation is y = 2\cdot x^{2} - 7\cdot x -4

8 0
3 years ago
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