If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
</span>
Answer:
x=3
y=3
Step-by-step explanation:
x = 6-y
-plug in (6-y) into first equation
2(6-y)+3y = 15
12-2y+3y=15
-2y+3y = 3
y=3
x=6-3
x=3
double check:
(2*3) + (3*3) = 6 + 9 = 15
3 + 3 = 6
You would divide 245 by 49 to get a
a= 5
