Answer:
12 and 14
Step-by-step explanation:
Let the even integers be x and x+2
three times the larger number is expressed as 3(x+2)
30 more than the smaller one is x + 30
Equating both expressions
3(x+2) = x +30
Find x
3x+6 = x+30
3x-x = 30-6
2x = 24
x = 12
The second integer is 12+2 = 14
Hence the required integers are 12 and 14
What are the statement options? If I had to guess it would be Jacqueline practiced 150 minutes all week and Cassie practiced 110 minutes so Jacqueline practiced more minutes in fewer sessions than Cassie.
Answer:
The equivalent factored form of this equation is (x² + 49)(x - 6)
Step-by-step explanation:
<em>x³ - 6x² + 49x - 294</em>
First, group the first and second terms together and group the last two terms together.
<em>(x³ - 6x²) + (49x - 294)</em>
Find the greatest common factor of both parentheses and factor them.
x²(x - 6) + 49(x - 6)
Now, since the two terms in the parentheses are the same, then we have factored the equation correctly.
So, the factored form of the equation is (x² + 49)(x - 6)
Given:
The two functions are:
To find:
The statement that best compares the graph of g(x) with the graph of f(x).
Solution:
The horizontal stretch is defined as:
...(i)
If 
, the function f(x) is horizontally stretched by factor 
.
If 
, the function f(x) is horizontally compressed by factor .
We have,
Using these functions, we get
...(ii)
On comparing (i) and (ii), we get
Since , the function f(x) is horizontally stretched by factor 
.
Hence, the correct option is D.
