Answer:
48y⁶w¹¹
Step-by-step explanation:
[-3y⁵][4y] → -12y⁶
×
[w³][-4w⁸] → -4w¹¹
______
48y⁶w¹¹
I am joyous to assist you anytime.
<span>At the animal shelter there are 56 more dogs than cats. If the total number of animals is 200 how many of each type are in the shelter?
dogs + cats = 200 eq I
</span>dogs = 56 + cats eq II
replace dogs in eq I
(56 + cats) + cats = 200 eq with one variable
56 + 2c = 200
2c = 200 - 56
2c = 144 /divided 2
<u>cats= 72</u>
dogs = 56 + cats = 56 + 72 = 128
<u>dogs = 126</u>
Answer:
(6y+1)(6y-1)
Step-by-step explanation:
To do this question you must know what Difference of Two Squares is.
The Difference of Two Squares is two terms that are squared and separated by a subtraction sign.
You can simplify them like this below
a²- b² = (a+b)(a-b)
36y²-1
36y² can become 6y×6y.
1 can become 1×1.
So, plugging it into the formula above, you will get
<u>(6y+1)(6y-1)</u>
Answer:
Step-by-step explanation: