Which expression is equivalent to x+2x+y+2y 3x3y 3x+3y 3+xy 6xy

Roscoe rides his bike at least 10 miles but not more than 30 miles. He rides at an average rate of 10.5 miles per hour. The amou

zheka24 [161]

Actually, the domain is the possible set of input values of a function that will make the function fit the specific criteria. In this case, the input value is m, where m is the number of miles that is travelled. The criteria is to travel at least 10 miles but not more than 30 miles, therefore the domain should be:

All real numbers from 10 to 30, inclusive

(should be real numbers not integer since any fractional number is included in the domain)

I cannot figure out why the choices are far from the answer.

3 0

3 years ago

Can you please help me with this! It's due in a couple hours.

castortr0y [4]

Answer:

f(2) = -5

Step-by-step explanation:

A point (x, y) lying on a function represents output value (y-value) of the function for any input value (x-value).

In other words y = f(x) for any input value of 'x'.

From the graph attached,

For the input value x = 2,

Output value of the function is y = -5

Therefore, f(2) = -5 will be the answer.

5 0

2 years ago

The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the

12345 [234]

Answer:

$4x^2-21x-2$

Step-by-step explanation:

Given that:

Difference of two trinomials is $x^2 - 10x + 2$

One of the two trinomials is $3x^2 - 11x - 4$

To find:

The other trinomial = ?

Four options are:

$2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2$

Solution:

Let the two trinomials be A and B.

Given A - B = $x^2 - 10x + 2$

B = $3x^2 - 11x - 4$

We have to find the other trinomial A.

A - B = $x^2 - 10x + 2$

A - ( $3x^2 - 11x - 4$ ) = $x^2 - 10x + 2$

$\Rightarrow$ A = $x^2 - 10x + 2$ + ( $3x^2 - 11x - 4$ )

$\Rightarrow$ A = $4x^2-21x-2$

So, the correct answer is $4x^2-21x-2$ .

3 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

makkiz [27]

Answer:

Step-by-step explanation:

$x + 2y + 3z = 12$

$z=\frac{12-x-2y}{3}$

Volume = $V=f(x,y) = xy(\frac{12-x-2y}{3} )$

find partial derivatives using product rule

$f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)$

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

6 0

2 years ago

Help me pls the questions are here

andreyandreev [35.5K]

3x + 7 = -x - 1
3x + 7 + = -1
4x + 7 = -1
4x = -1 - 7
4x = -8
x = -2

1 - 2x + 5 = 4x - 3
-2x + 6 = 4x - 3
6 = 4x - 3 + 2x
6 = 6x - 3
6 + 3 = 6x
9 = 6x
x = 6/9
x = 2/3

i helped you with the first two questions so you can see how you can solve it.

hope this helps, God bless!

6 0

2 years ago