Add all of the x’s up you get 223.8
Hello there,
I hope you and your family are staying safe and healthy during this winter season.

We need to use the Quadratic Formula*
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Thus, given the problem:

So now we just need to plug them in the Quadratic Formula*
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As you can see, it is a mess right now. Therefore, we need to simplify it
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Now that's get us to the final solution:
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~Garebear
Answer:
<em>The distance from the point to the line is approximately 3.2 units</em>
Step-by-step explanation:
<u>Distance From a Point to a Line</u>
Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.
If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is

The line is given by the equation:
y=3x. We need to transform it into the specified form.
Subtracting 3x:
y - 3x = 0
Comparing with the general form of the line, we have
a=-3, b=1, c=0
The point (xo,yo) is (-1,7), thus:





The distance from the point to the line is approximately 3.2 units
Answer:
1
Step-by-step explanation:
Given :
Mean, μ = 4
Standard deviation, s = 0.8
Sample size, n = 30
The distribution is independent.
Z = (x - μ) / s /sqrt(n)
Probability that downtime period is between 1 and 5
P(1≤ x ≤ 5) :
[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]
[(1 - 4) / (0.8 /sqrt(30))] ≤ Z ≤ [(5 - 4) / (0.8 /sqrt(30)]
[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]
P(-20.539602 ≤ Z ≤ 6.8465342)
P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)
P(Z ≤ 6.8465342) = 1 (Z probability calculator)
P(Z ≤ - 20.5396) = 0 (Z probability calculator)
1 - 0 = 1
When you multiplied both sides by a NEGATIVE number, what WAS negative became positive, and what WAS positive became negative! Everything that was larger became small, and what was smaller became large. Everything REVERSED