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Lisa [10]
3 years ago
10

The temperature on Tuesday is -2∘C. If the temperature rises by 15∘C, what is the new temperature?

Mathematics
2 answers:
Tom [10]3 years ago
8 0

Answer:

13∘C

Step-by-step explanation:

15∘C + - 2∘C = 15∘C - 2∘C

15∘C - 2∘C = 13∘C

Vaselesa [24]3 years ago
8 0

Answer:

13 C

Step-by-step explanation:

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i dont know how to solve this questions without a graphing on a calculator but i can't use calculator for this question pls help
hoa [83]

Answer:

<em><u>D</u></em>

Step-by-step explanation:

When the denominator is equal to 0, the function doesn't exist. So factor the bottom, luckily its already partially factored.

(x^2 + 8x + 12) = (x+2)(x+6)

So now the denominator is (x+2)(x+6)(x-3)

The function doesn't exist when x = -2, -6, 3

Now we know there are 3 total discontinuities.

<u>A and B can be eliminated</u>

Since there is an (x+2) on the top and the bottom, they don't affect the shape of the function, but only causes a removable discontinuity when x = -2.

However, (x+6) and (x-3) are only on the bottom, so they DO change the shape, so they are non-removable

The answer therefore is 1 removable and 2 non-removable; D

7 0
3 years ago
Read 2 more answers
50 points :] !!
nasty-shy [4]

Given,

LP = 15, PR = 9

Point P lies on the line segment PR. It would mean that,

LP + PR = LR

⇒LR = 15 + 9

⇒ LR = 24

Hence, "LR = 24 because LP + PR = LR according to the Segment Addition Postulate, and 15 + 9 = 24 using substitution" is the correct option.

6 0
3 years ago
Graph the following systems of equations and determine the solution of the system .​
Zanzabum

Answer:

We can find the solution to a system of equations by graphing the equations. Let's do this with the following systems of equations:

8 0
3 years ago
Find all real zeros of the function y=2x-4
Ber [7]
For this case we have the following linear function:
 y = 2x-4&#10;
 What we must do is equal the function to zero or equivalently, substitute the value of y = 0 in the given function.
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 2x - 4 = 0&#10;
 From here, we clear the value of x.
 We have then:
 2x = 4&#10;&#10;x = 4/2&#10;&#10;x = 2
 Answer:
 
all real zeros of the function y = 2x-4 are:
 
x = 2
5 0
4 years ago
Quadrilateral ABCD is located at A(-2,2), B(-2,4) and D(2,2). The quadrilateral is then transformed using the rule (x+2,y-3) to
Kay [80]
The rule is x+2, y-3 so you apply it to each of these coordinates. Right 2, down 3.
A(-2,2) -> A'(0,-1)
B(-2,4) -> B'(0, 1)
D(2,2) -> D'(4,-1)
7 0
4 years ago
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