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sertanlavr [38]
3 years ago
9

Someone please help me answer this!!

Mathematics
2 answers:
attashe74 [19]3 years ago
8 0
5.5x10^ he would be right
pochemuha3 years ago
5 0

Answer:

5.5 x 10 ^ 0

Step-by-step explanation:

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Find the perimeter and area of the polygon shown below.
Mars2501 [29]

Answer:

A. P = 72 feet, A = 300 square feet

Step-by-step explanation:

✔️Perimeter = sum of all sides of the polygon = 15 + 16 + 17 + 8 + 16 = 72 ft

✔️Area of the polygon = area of a trapezoid = ½(a + b)h

Where,

a = 16 ft

b = 16 + 8 = 24 ft

h = 15 ft

Substitute

Area = ½(16 + 24)15

Area = ½(40)15

Area = 300 ft²

4 0
3 years ago
Are the expressions x + x + 1 + x + 2 + x + 1 + x and 5x + 4 equivalent? Why or why not?
egoroff_w [7]

Answer:

yes

they are equivalent because lets say the X = 3 then you would have to answer

3 + 3 + 1 + 3 + 2 + 3 + 1 + 3

and that would = 19

and then on the other equation

5 x 3 + 4 = 19

So the both equal the same.

PLZ MARK ME BRAINLIEST

3 0
3 years ago
Brainliest!!! just help me with one question!! :)
geniusboy [140]
C, 5 slices I believe!
5 0
3 years ago
Read 2 more answers
Need help answering these five geometry questions I need answers
andriy [413]

Answer:

If you help me I will help you

Step-by-step explanation:

3 0
4 years ago
Please help QUICKLY! please explain your answer, please give the correct answer
alisha [4.7K]

Answer:

  • 0: 0.7056
  • 1: 0.2688
  • 2: 0.0256

Step-by-step explanation:

When events are independent, the probability of some sequence of them is the product of the probabilities of the individual events in that sequence.

The probability of a child having spina bifida is 16% = 0.16, so the probability that the child will not have the condition is 1 - 0.16 = 0.84. The probability that 0 of 2 children will have spina bifida is ...

  p(0 for 2) = p(0 for 1)×p(0 for 1) = 0.84×0.84 = 0.7056

__

There are two ways that 1 of 2 children can have spina bifida: either the first one does, or the second one does. These are mutually exclusive conditions, so their probabilities add:

  p(1 for 2) = p(1 for 1)×p(0 for 1) +p(0 for 1)×p(1 for 1) = 0.16×0.84 +0.84×0.16

  p(1 for 2) = 0.2688

__

There is one way both children can have spina bifida:

  p(2 for 2) = p(1 for 1)×p(1 for 1) = 0.16×0.16 = 0.0256

__

In summary, our probability distribution is ...

  p(X=0) = 0.7056

  p(X=1) = 0.2688

  p(X=2) = 0.0256

8 0
3 years ago
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