I've answered this before, but only partially. I'm not sure about the second part, but I think the first one is 10
Answer:
but I will not let him die
Step-by-step explanation:
v I I 56r6eyci fee will notify include his
Answer:
-3x(2y^5+5x^3-3)
Step-by-step explanation:
-6xy^5 - 15x^4 + 9x
-6xy^5-15xx^3+9x
2*3xy^5+5+3xx^3z+3*3x
Factor:
-3x(2y^5+5x^3-3)
Answer:
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
Step-by-step explanation:
1. Let's check all the information provided to answer the question:
Time of Thomas flight delay = 1 5/6 hours
Time of normal flight = x hours
2. How long did the trip finally take?
For calculating how long the trip finally took, we need to do the following sum:
Time of normal flight + Time of delay
Like we don't know the time of the normal flight, we will define it as x, then:
x + 1 5/6 hours
x + 1 hour and 50 minutes ⇒ 5/6 of an hour = 5/6 * 60 minutes = 50 minutes
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
