Help please, i need it asap. tyty

1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno

Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, $H_0$ : $\mu$ = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, $H_1$ : $\mu\neq$ 100 {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ N(0,1)

where, Xbar = sample mean score = 113

s = population standard deviation = 15

n = sample of students = 144

So, test statistics = $\frac{113-100}{\frac{15}{\sqrt{144} } }$

= 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0

4 years ago

Xin orders 5 identical loaves of bread from the website of a bakery. The total shipping weight is 9 pounds, as molded on the bal

svetlana [45]

Answer: 1.8 pounds per loaf of bread

Step-by-step explanation:

Total shipping weight = 9 pounds

# of loaves of bread = 5

9/5 = 1.8 pounds per loaf

6 0

3 years ago

Match the function with its graph.

kondor19780726 [428]

Answer:

Option a. 1C, 2A, 3B, 4D.

Step-by-step explanation:

1) We know that tan(x)=sin(x)/cos(x). If x=0, sin(x)=0 and cos(x)=1 then tan(x)=0. For that reason, we know that the graph passes through the point (0,0).

If x=45, then sin(45)= $\frac{\sqrt{2}}{2}$ and cos(45)= $\frac{\sqrt{2}}{2}$ . Thus tan(45)=1. The only graph that passes through the point (0,0) and is possitive when x=45 is the graph C.

2) We know that cot(x)=cos(x)/sin(x). If x=0, sin(x)=0 and cos(x)=1 then tan(x)=+∞. For that reason, we know that the graph has an asymptote in y=0, in other words, it never crosses the y-axis.

If x=45, then sin(45)= $\frac{\sqrt{2}}{2}$ and cos(45)= $\frac{\sqrt{2}}{2}$ . Thus cot(45)=1. The only graph that has an asymptote in y=0 and is possitive when x=45 is the graph A.

3) We know that -tan(x)=-sin(x)/cos(x). If x=0, sin(x)=0 and cos(x)=1 then -tan(x)=0. For that reason, we know that the graph passes through the point (0,0).

If x=45, then sin(45)= $\frac{\sqrt{2}}{2}$ and cos(45)= $\frac{\sqrt{2}}{2}$ . Thus -tan(45)=-1. The only graph that passes through the point (0,0) and is negative when x=45 is the graph B.

) We know that -cot(x)=-cos(x)/sin(x). If x=0, sin(x)=0 and cos(x)=1 then tan(x)=-∞. For that reason, we know that the graph has an asymptote in y=0, in other words, it never crosses the y-axis.

If x=45, then sin(45)= $\frac{\sqrt{2}}{2}$ and cos(45)= $\frac{\sqrt{2}}{2}$ . Thus -cot(45)=-1. The only graph that has an asymptote in y=0 and is negative when x=45 is the graph D.

8 0

4 years ago

Please help i am not passing my math class i will give you the brainliest I am struggling

mash [69]

Answer:

x=-6

Step-by-step explanation:

(8x-15)=(3x-45)

4 0

3 years ago

Just type the numerical solution.<br> 2 (n + 4) = 8-n

Vlad1618 [11]

2 (n+4)=8-n like this

4 0

3 years ago