All categories

3 years ago

Can some one help me with this

Mathematics

1 answer:

Blizzard [7]3 years ago

6 0

Answer:

273/1000

Step-by-step explanation:

You might be interested in

Round 243.583 to the nearest tenth *

Nastasia [14]

Answer: 243.6

Step-by-step explanation:

For us to solve the question and round off 243.583 to the nearest tenth. First, we need to look at the number beside the tenth number which is 8.

Since 8 is more than 4, we simply add 1 to the tenth number which implies that we add 1 to the number in tenth place which is 5. Adding one means the number change to 6. Therefore, rounding 243.583 to the nearest tenth will be 243.6.

4 0

3 years ago

Jim

stealth61 [152]

yes i agree because if all the integers are positive, the answer stays positive which means if you know your integer rules: a positive divide by a positive it stays positive. its the same thing for all the other operations. hope this helps.

6 0

3 years ago

Read 2 more answers

X-4y=28 2x+y=2 Elimination

makvit [3.9K]

$\left\{\begin{array}{ccc}x-4y=28\\2x+y=2&\text{multiply both sides by 4}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-4y=28\\8x+4y=8\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad9x=36\qquad\text{divide both sides by 9}\\.\qquad\boxed{x=4}\\\\\text{Put the value of x to the second equation:}\\\\2(4)+y=2\\8+y=2\qquad\text{subtract 8 from both sides}\\\boxed{y=-6}\\\\Answer:\ \boxed{x=4\ and\ y=-6\to(4,\ -6)}$

3 0

3 years ago

4/16 divided by 7/12 (simplified)

Leya [2.2K]

Answer:

$\frac{3}{7}$

Step-by-step explanation:

$\frac{4}{16} *\frac{12}{7}\\\\\frac{4}{4} * \frac{3}{7} \\\\1*\frac{3}{7} = \frac{3}{7}$

HAPPY:) I explained it!!

8 0

3 years ago

Himpunan penyelesaian pertidaksamaan nilai mutlak |2x-4| > |3x+2|

Stells [14]

Answer:

The solution in interval notation is:

$(-6,\frac{2}{5})$ .

The solution in inequality notation is:

$-6$ .

Step-by-step explanation:

I think you are asking how to solve this for $x$ .

Keep in mind $|x|=\sqrt{x^2}$ .

$|2x-4|>|3x+2|$

$\sqrt{(2x-4)^2}>\sqrt{(3x+2)^2}$

If $\sqrt{u}>\sqrt{v}$ then $u>v$ .

$(2x-4)^2>(3x+2)^2$

Subtract $(2x-4)^2$ on both sides:

$0>(3x+2)^2-(2x-4)^2$

Factor the difference of squares $a^2-b^2=(a-b)(a+b)$ :

$0>((3x+2)-(2x-4))((3x+2)+(2x-4))$

Simplify inside the factors:

$0>(x+6)(5x-2)$

$(x+6)(5x-2)$

The left hand side is a parabola that faces up. I know this because the degree is 2.

The zeros of the the parabola are at x=-6 and x=2/5.

We can solve x+6=0 and 5x-2=0 to reach that conclusion.

x+6=0

Subtract 6 on both sides:

x=-6

5x-2=0

Add 2 on both sides:

5x=2

Divide both sides by 5:

x=2/5

Since the parabola faces us and $(x+6)(5x-2)$ then we are looking at the interval from x=-6 to x=2/5 as our solution. That part is where the parabola is below the x-axis. We are looking for where it is below since it says the where is the parabola<0.

The solution in interval notation is:

$(-6,\frac{2}{5})$ .

The solution in inequality notation is:

$-6$ .

6 0

4 years ago