Solving systems of equation using elimination
1 answer:
Answer:
2x+2y = 8
x – 2y = 4
3x=12
x=12/3=4
x=4
2x+2y=8
2(4) + 2y = 8
8+2y = 8
2y=8-8
2y=0
y=0/2=0
2(4)+2(0)=8
8+0=8
x+y=8
x-y=4
2x=12
x=12/2=6
6+y=8
y=8-6=2
6+2=8
2x+2y=4
x-y=4
2x+2y=4
2(x-y=4)
2x+2y=4
2x-2y=8
4x=12
x=12/4=3
2(3)+2y=4
6+2y=4
2y=4-6
2y=-2
y=-2/2=-1
2(3)+2(-1)=4
6+-2=4
x+2y=8
-(x+3y=4)
x+2y=8
-x-3y=-4
-1y=4
y=4/-1=-4
x+2(-4)=8
x+-8=8
x=8+8=16
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