What is the equation of the line that passes through the points (5,-1) and (-5,0)?

Write the following ratio in the simplest form 1/2:3/5

Alla [95]

Answer:

Step-by-step explanation:

$\frac{1}{2}:\frac{3}{5}=\frac{1*5}{2*5}:\frac{3*2}{5*2}\\\\=\frac{5}{10}:\frac{6}{10}\\\\= 5:6$

5 0

3 years ago

A compound event may consist of dependent or independent events

Korolek [52]

The answer to your question is true

6 0

4 years ago

F(t)=30(0.97)∧t = rate of change

Vedmedyk [2.9K]

Hey there, Lets solve this together.

 $F(t)=30(0.97)^t$

$A = (p+r)^t$

The variable (R) will be representing the rate as a decimal.

When you solve for (R) multiply by 100 to get the percentage. A percentage is a rate, number, or amount in each hundred.

"0.97" will be replaced by "(97/100)"

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the given equation

$Ft-((30))97/100) * t) = 0$

Rewrite the whole as a fraction using 10 as the denominator :

$ft = ft/1 = ft * 10/10$

The equation now takes the shape :
t • (10f-291) = 0

 f = 291/10 = 29.100

 t = 0

Positive = Growth

Negative = Decay

 $1 + r = .97$

 $r = -0.03$

5 0

3 years ago

A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angl

Nata [24]

Answer:

m∠1 + m∠2 = 180°

Step-by-step explanation:

An interior angle and its exterior angle are supplementary (they add up to 180°).

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5 0

4 years ago

Read 2 more answers

A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation

Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$