N/-5 = -30 solve for N

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

150

Step-by-step explanation:

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Write an equation in point-slope form for the line that passes through each point with the given slope.

castortr0y [4]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-4})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{0}[x-\stackrel{x_1}{(-3)}]\implies y+4=0(x+3) \\\\\\ y+4=0\implies y=-4$

5 0

3 years ago

Is it parallel or is it perpendicular?

zavuch27 [327]

It is parallel, which means that the new line should have the same slope of the given line $y=-5/4 x+7$
and the slope is the coefficient of x
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
$slope= \frac{y-y1}{x-x1}$
where (x1,y1) is the point by which the new line passes through

$\frac{-5}{4}=\frac{y-(-4)}{x-1}$
$\frac{-5}{4}= \frac{y+4}{x-1}$
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y= $\frac{-5}{4}x - \frac{11}{4}$