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3 years ago

Use a number line to solve 235 + 123

2 answers:

5 0

You can draw a number line and count by 5 or 10s until you get the answer 358.
Start with 123 and then count by 5 or 10s until you get 235, count the numbers in between and youll get 358

Alex3 years ago

4 0

The answer is 358 without using a number line just add it up

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Tell whether the number is prime or composite 68

Readme [11.4K]

68 is a composite number

3 0

3 years ago

What is 87.92 rounded to the nearest tenth

alex41 [277]

Answer:

87.92 rounded to the nearest tenth would be 87.9 because you wouldn't round up unless the number after the 9 was 5 or higher.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the percentage between 1192.64 and 819.73

Licemer1 [7]

1192.64-819.73 is 372.91

so... if we take 1192.64 to be the 100%, how much is 372.91 in percentage then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1192.64&100\\
372.91&p
\end{array}\implies \cfrac{1192.64}{372.91}=\cfrac{100}{p}\implies p=\cfrac{372.91\cdot 100}{1192.64}$

3 0

3 years ago

50 POINTS & BRAINLIEST!!!! HELP ASAP!!!

Allisa [31]

6(2x - 11) + 15 = 21

First step use distributive property on the left side to remove the parenthesis, to do this multiply 6 by each term inside the parenthesis:

12x - 66 + 15 = 21

Second step, simplify the left side by combining the like terms:

12x - 51 = 21

Third step, add 51 to both sides of the equation:

12x = 72

Last step, divide both sides by 12:

x = 72/12

x = 6

3 0

3 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

3 years ago