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Olenka [21]
3 years ago
6

Section 1

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

1/2

Step-by-step explanation:

A nickel doesn't matter - it is just 1/2.

Hope this helps :D

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What is the percent decrease of 80 to 64
devlian [24]
The amount of decrease is  (80 - 64)  =  16

The fraction of decrease is the fraction of the original amount that disappeared.

That fraction is      (16 / 80)  =  1/5  =  0.2

To change a decimal to a percent,
move the decimal point 2 places that way ==> .

                             0.2  =  20%
6 0
3 years ago
A parking garage charges an initial fee of $7.00 for up to 2 hours of parking, and an hourly rate for each additional hour
aliina [53]

Answer:

$7.00*2h=r

I need more information to answer the question correctly.

Step-by-step explanation:


7 0
3 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
Read 2 more answers
Look at the attachment<br>Simplified it too <br>pls take it seriously ​
Phantasy [73]

\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}

\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}

\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}

\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)

5 0
2 years ago
Four friends plan to rent a car to go on a camping trip. They will drive a total of 450 miles. The cost of gasoline is​ $2.20 pe
Vlada [557]

Answer:

t = (m / g) * p

Step-by-step explanation:

Since we are given a variable for every part of the equation that we need we can go ahead and create the following equation where t equals the total cost

t = (m / g) * p

In this equation, we need to first divide the total number of miles by the number of miles that the car gets per gallon. This would give us the total number of gallons that the car would use during the entire trip. We then multiply the number of gallons by the price per gallon to get the final cost of the entire trip.

4 0
3 years ago
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