Wilda can do the job in 4 hours ... she does 1/4 (or 0.25) of it each hour.
Karla can do it in 5 hours ... she does 1/5 (or 0.2) of it each hour.
Wilda worked alone for 1 hour ... 0.25 of the job was done before her helper
arrived. So only 0.75 of the job remained to be done together.
Working together, they accomplish (0.25 + 0.2) = 0.45 of the job in 1 hour.
How many times do they need to do 0.45 of the job in order to finish
the 0.75 of it that remains ? That's the number of hours it will take them,
working together.
0.75 / 0.45 = <em>1 and 2/3</em>
After Wilda worked alone for 1 hour and Karla came along to join her, it will
take them another <em>1 hour and 40 minutes</em> to finish the job and go for a swim.
At the 3/4 marker, the rider can collect a green ribbon and a blue ribbon.
Because 3/4 is the 3rd stop for a blue ribbon and 3/4 is the 6th stop for a green ribbon.
Answer:
c^2=33^2+37^2-2(33)(37)cos120(i don't know for sure tho)
Step-by-step explanation:
LAW OF COSINES
Velocity=Distance/Time
Time(t)=Distance/Velocity
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