Answer:
I got 6-7-9-5
Step-by-step explanation:
C and D is 1 more than A and B while having the lowest number, which also means it has the highest number. I started with giving C 9 and subtracting 4 and giving D 5, then I chose 2 numbers between 9 and 5 for A and B. If I gave B 8, then A would have to be 5, but D is already the lowest number so I gave B 7 and A 5 which works out with the requirements. I guess I got lucky when choosing 9 for C, but if 9 didn't work, then I'd go down to 8. I suspected 9 would work because B had to be 7 or 8 while not being the highest number and being less then C and D while being added to A. Make sure to leave feedback!
Let n represent the interger l, the three consective intergers are represented by
The second one represent
Simplify both sides
The intergers are 16,18,20
The sum of the other 2 sides must be greater than 13.
<em>Hello there, and thank you for posting your question here on brainly.
</em>Short answer: x = -5
<em>
</em>Why?
The solution to this has a lot of steps. Subtract two from both sides. (2+7/x=3/5 --> 7/x=-7/5) Multiply both sides by x. (7/x=-7/5 --> 7=-7x/5) Multiply both sides by 5. (7=-7x/5 --> 35=-7x) Divide both sides by -7. (-5=x) x = -5
<em>Hope this helped you! ♥</em>
Answer:
a+b = 12
Step-by-step explanation:
There are 36 possible outcomes for rolling two dice. Let A be the number rolled by Abed and D be the number rolled by Dawn. The sample space, in the format [A,D], of all of the possibilities in which Dawn's number is larger is:
[5,6]
[4,5] [4,6]
[3.4] [3,5] [3.6]
[2,3] [2.4] [2,5] [2.6]
[1,2] [1,3] [1.4] [1,5] [1.6]
There are 15 ways out of 36 possible ways of Dawn getting the higher number. In the simplest form: