Answer:
The answer to your question is: h = 14.5 in
Step-by-step explanation:
Data
radius = 5 in
Volume = 725 π in³
height = ?
Formula
Volume = 2πr²h
Substitution
725 π in³ = 2πr² h
h = 725π / 2πr²
h = 725 / 2(5)²
h = 725 / 50
h = 14.5 in
C = pi * r ^squared
r = is radius
square the radius, multiple by r
or
2 x pi x r
Answer:
D
Step-by-step explanation:
intercept is -4 and slope is rise over run which is 3/1 = 3
put into slope intercept form to achieve answer D
Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector


Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Answer:
793 liters of washing fluid is needed
Step-by-step explanation:
step 1
Find the slant height of the triangular faces of pyramid
we know that
The lateral area of a square pyramid is equal to the area of its four triangular faces
so
![LA=4[\frac{1}{2}bl]](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7Dbl%5D)
where
b is the base of triangle (is the same that the length of the square base)
l is the slant height
To find out the slant height we need to apply the Pythagorean Theorem
so

we have


substitute



step 2
Find the lateral area of the pyramid
![LA=4[\frac{1}{2}bl]](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7Dbl%5D)
we have


substitute
![LA=4[\frac{1}{2}(35.42)(27.96)]](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2835.42%29%2827.96%29%5D)

step 3
Find out how much window washing fluid is needed
we know that
2 L of washing fluid cover 5 square meters
so
using proportion

Round up
793 liters of washing fluid is needed